How do you write the expression #sin3cos1.2-cos3sin1.2# as the sine, cosine, or tangent of an angle?

Question

10818 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-22T08:24:38

The answer is #=sin1.8#

We use

#sin(A-B)=sinAcosB-sinBcosA#

Here,

#A=3#

#B=1.2#

Therefore,

#sin3cos1.2-cos3sin1.2=sin(3-1.2)=sin1.8#