A container with a volume of #48 L# contains a gas with a temperature of #140^o K#. If the temperature of the gas changes to #810 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-01-24T13:17:14

The volume is #=277.7L#

We apply Charles's Law

#V_1/T_1=V_2/T_2#

#V_1=48L#

#T_1=140K#

#T_2=810K#

#V_2=(V_1T_2)/T_1#

#=48*810/140=277.7L#