How do you solve #30< 5x \leq 40#?

1 Answer
Jan 26, 2017

See the entire solution process below:

Explanation:

To solve this divide each portion of the system of inequalities by #color(red)(5)# to solve for #x# while keeping the system of inequalities balanced:

#30/color(red)(5) < (5x)/color(red)(5) <= 40/color(red)(5)#

#6 < (color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5)) <= 8#

#6 < x <= 8#