Question

Question #789d1

Answer 1

`= 1/(9x^-1)` or `x/9`

Explanation:

`((3x)^2(3x)^-3)/(3x^-2)`

`= (3x)^(2+(-3))/(3x^-2)`, use `a^m*a^n = a^(m+n)`

`= (3x)^-1/(3x^-2)=1/((3x)(3x^-2))`, use `a^-m=1/a^m`

`=1/(3*x*3*x^-2)`

`= 1/(9x^-1)` or `x/9`