Question #2c4f7

1 Answer
Jan 27, 2017

ans. the derivative is (-e^(-2y))/(x-1)^2, where y =ln sqrt((x+1)/(x-1)).

Explanation:

see, at first let y =ln sqrt((x+1)/(x-1))
or e^y = sqrt((x+1)/(x-1))
or e^(2y) =(x+1)/(x-1) (sqaring)
now differenting the above w.r.t x we get ,
dy/dx 2e^(2Y)=((x-1)-(x+1))/(x-1)^2 by (d(u/v)/dx) method
or dy/dx e^(2y) =-1/(x-1)^2
or we get dy/dx =-e^(-2y)/(x-1)^2 where y=lnsqrt((x+1)/(x-1)).