How do you solve #5= \frac { 9+ t } { 4}#?

Question

977 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-27T16:29:36

#t=11#.

#5=(9+t)/4#

Mulitply BOTH sides by #4#.

#5xx4=(9+t)/cancel4xxcancel4=20=9+t#

Subtract #9# FROM BOTH SIDES:

#20-9=cancel9+t-cancel9#

#t=11#

All I have done here is to manipulate BOTH sides of the equality equivalently. What I did to one side, I must do to the other.

Answer 2 · 2017-01-27T16:30:13

See the entire solution process below:

First, multiply each side of the equation by #color(red)(4)# to eliminate the fraction and to keep the equation balanced.

#5 xx color(red)(4) = (9 + t)/4 xx color(red)(4)#

#20 = (9 + t)/color(red)(cancel(color(black)(4))) xx cancel(color(red)(4))#

#20 = 9 + t#

Now, subtract #color(red)(9)# from each side of the equation to solve for #t# while keeping the equation balanced:

#20 - color(red)(9) = 9 + t - color(red)(9)#

#11 = 9 - color(red)(9) + t#

#11 = 0 + t#

#11 = t#

#t = 11#