How do you find the sum of the infinite geometric series $1/8+1/32+1/128+...$ ?

Question

11012 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-28T22:50:38

$1/6$

First term, $a$ , is $1/8$ .
Common ratio, $r$ , is $1/4$ .
Sum of a G.P. to infinity is $a/(1-r)$ which is $(1/8)/(1-1/4)=1/6$

How do you find the sum of the infinite geometric series 1/8+1/32+1/128+...1/8+1/32+1/128+...?