How do you find the x and y intercept of #5x-3y=15#?

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Answer 1 · 2017-01-29T00:02:07

The #x-#intercept is #(3,0)#
The #y-#intercept is #(0,5)#

The #x# and #y# intercepts of of a linear equation can be found by plugging #0# in for each variable and finding the solution for the other variable.

The #x#- intercept is found where #y=0#
The #y#- intercept is found where #x=0#

Solve for each independently.

#5x - 3y = 15#

#5x - 3(0) = 15#

#5x = 15#

#(cancel(5)x)/cancel5 = 15/5#

#x=3#

The #x-#intercept is #(3,0)#

#5x - 3y = 15#

#5(0) - 3y = 15#

#3y = 15#

#(cancel(3)y)/cancel3 = 15/3#

#y=5#

The #y-#intercept is #(0,5)#