How do you factor #5d^2+6d-8#?

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Answer 1 · 2017-01-29T01:00:19

The factor of #5d^2+6d-8# is

#(5d-4)(d+2)#

To factors the trinomial
#5d^2+6d-8#

We take the factors of the first coefficient #5 = 5*1#
We take the factors of the constant term #8 = 1*8 or 2*4#

We look for an arrangement of the factors that will subtract to get #+6#

#5*(+2) = 10#
#1 * (-4) = -4#
#10-4 = +6

Make #5d# and #+2# the outer factors
Make #1d# and #-4# the inner factors

#(5d-4)(d+2)#