How do you write the series #1/2+1/4+1/8+1/16+...# using sigma notation?

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Answer 1 · 2017-01-30T16:55:54

#1/2+1/4+1/8+1/16+...#
#=1/2^1=1/2^2+1/2^3+1/2^4+...#
#=sum_(m=1)^(oo)1/2^m," or, simply, we can say,"#
#sum_1^oo1/2^m#.