How do you write the series $1/2+1/4+1/8+1/16+...$ using sigma notation?

Question

9593 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-30T16:55:54

$1/2+1/4+1/8+1/16+...$
$=1/2^1=1/2^2+1/2^3+1/2^4+...$
$=sum_(m=1)^(oo)1/2^m," or, simply, we can say,"$
$sum_1^oo1/2^m$ .

How do you write the series 1/2+1/4+1/8+1/16+...1/2+1/4+1/8+1/16+... using sigma notation?