The gas inside of a container exerts #7 Pa# of pressure and is at a temperature of #310 ^o K#. If the pressure in the container changes to #15 Pa# with no change in the container's volume, what is the new temperature of the gas?

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Answer 1 · 2017-02-01T08:35:21

The temperature is #=664.3K#

We apply Gay Lussac's Law

#P_1/T_1=P_2/T_2#

#P_1=7 Pa#

#T_1=310K#

#P_2=15Pa#

#T_2=P_2/P_1*T_1#

#=15/7*310=664.3K#