What is the Cartesian form of #(-1,(22pi)/4))#?

1 Answer
Feb 2, 2017

(0,1)

Explanation:

First of all, angle #(22pi)/4# is #(11pi)/2# which is equivalent to #4pi +(3pi)/2# that is #(3pi)/2# because #4pi# just adds 0 to the angle #(3pi)/2#

So, first we move by an angle of #(3pi)/2# radians anti-clockwise
around the pole from starting position of 0 radians. This is shown in the figure below, as point P. Now since r= -1, we move in the opposite direction of r=1 for angle of #(3pi)/2# . This positions has been indicated by point P' in the figure.

As is now evident from the figure, cartesean coordinates for#(-1, (22pi)/4)# would be point P' (0,1)

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