How do you solve #5(x+2) = 7(x-2)#?
1 Answer
Feb 3, 2017
Explanation:
distribute the brackets on both sides of the equation.
#rArr5x+10=7x-14# collect terms in x on the left side and numeric values on the right side.
subtract 7x from both sides.
#5x-7x+10=cancel(7x)cancel(-7x)-14#
#rArr-2x+10=-14# subtract 10 from both sides.
#-2xcancel(+10)cancel(-10)=-14-10#
#rArr-2x=-24# To solve for x, divide both sides by - 2
#(cancel(-2) x)/cancel(-2)=(-24)/(-2)#
#rArrx=12#
#color(blue)"As a check"# Substitute this value into the equation and if the left side equals the right side then it is the solution.
#"left side "=5(12+2)=5xx14=70#
#"right side "=7(12-2)=7xx10=70#
#rArrx=12" is the solution"#