How do you solve #-15B-14=-4#?

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Answer 1 · 2017-02-05T10:23:59

See the entire solution process below:

Step 1) Add #color(red)(14)# to each side of the equation to isolate the #B# term while keeping the equation balanced:

#-15B - 14 + color(red)(14) = -4 + color(red)(14)#

#-15B - 0 = 10#

#-15B = 10#

Step 2) Divide each side of the equation by #color(red)(-15)# to solve for #B# while keeping the equation balanced:

#(-15B)/color(red)(-15) = 10/color(red)(-15)#

#(color(red)(cancel(color(black)(-15)))B)/cancel(color(red)(-15)) = (5 xx 2)/color(red)(5 xx -3)#

#B = (color(red)(cancel(color(black)(5))) xx 2)/color(red)(cancel(5) xx -3)#

#B = -2/3#