How do you solve #(a-15)/6=20#?

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Answer 1 · 2017-02-05T12:37:44

#a=135#

#(a-15)/6 = 20" "larr# multiply both sides by 6

#a-15 = 6xx20" "# add 15 to both sides

#a = 120+15#

#a = 135#

To check, substitute the solution into the original equation.

#LHS= (135-15)/6 " " and RHS =20#

#=120/6#

#=20#

LHS = RHS, therefore the solution is correct.