Question

How much perchloric acid will react with a `20*mL` volume of sodium hydroxide whose concentration is `0.060*mol*L^-1`?

Answer 1

This is something that you will have to address yourself.

Explanation:

We examine the reaction of the strong base, `NaOH`, with `HClO_4`, according to the rxn:

`NaOH(aq) + HClO_4(aq) rarr NaClO_4(aq) + H_2O(l)`

`"Moles of sodium hydroxide"=20.0xx10^-3Lxx0.060*mol*L^-1=1.20xx10^-3*mol.`

Now clearly, we will reach a stoichiometric endpoint when we add `1.20xx10^-3*mol` `"perchloric acid"` solution.

This represents a volume of `(1.20xx10^-3*molxx10^3*mL*L^-1)/(0.040*mol*L^-1)=30*mL`.