How do you find the sum or difference of #(-3d^2-8+2d)+(4d-12+d^2)#?

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Answer 1 · 2017-02-08T22:46:07

See the entire solution process below:

First, remove the terms from within the parenthesis being careful to handle to the sign of each individual term correctly:

#-3d^2 - 8 + 2d + 4d - 12 + d^2#

Next, group like terms together:

#-3d^2 + d^2 + 2d + 4d - 12 - 8#

Now, combine like terms:

#-3d^2 + 1d^2 + 2d + 4d - 12 - 8#

#(-3 + 1)d^2 + (2 + 4)d - 20#

#-2d^2 + 6d - 20#