How do you simplify and find the excluded value of $(X^2+3x-10)/(x^2+x-20)$ ?

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Answer 1 · 2017-02-11T06:53:47

$(x-2)/(x-4)$ ; the excluded value is $x=-5$

Since

$x^2+3x-10=(x+5)(x-2)$

and

$x^2+x-20=(x+5)(x-4)$

the expression is:

$(x^2+3x-10)/(x^2+x-20)=(color(red)((x+5))(x-2))/(color(red)((x+5))(x-4))$

Then the excluded value is $x=-5$

and you can simplify to:

$(x-2)/(x-4)$

How do you simplify and find the excluded value of (X^2+3x-10)/(x^2+x-20)(X^2+3x-10)/(x^2+x-20)?