First, remove the terms in parenthesis being sure to handle the signs for the individual terms correctly:
#-x - 3 + 3/4x + 5 = 0#
Next, multiply each side of the equation by #color(red)(4)# to eliminate the fraction while keeping the equation balanced:
#color(red)(4)(-x - 3 + 3/4x + 5) = color(red)(4) xx 0#
#(color(red)(4) xx -x) - (color(red)(4) xx 3) + (color(red)(4) xx 3/4x) + (color(red)(4) xx 5) = 0#
#-4x - 12 + (cancel(color(red)(4)) xx 3/color(red)(cancel(color(black)(4)))x) + 20 = 0#
#-4x - 12 + 3x + 20 = 0#
Then, combine line terms:
#-4x + 3x - 12 + 20 = 0#
#(-4 + 3)x + 8 = 0#
#-x + 8 = 0#
Now, add #color(red)(x)# to each side of the equation to solve for #x# while keeping the equation balanced:
#color(red)(x) - x + 8 = color(red)(x) + 0#
#0 + 8 = x#
#8 = x#
#x = 8#
