Question

Question #d66eb

Answer 1

`lim_(h->0) ((x+h)^2-x^2)/h = 2x`

Explanation:

`lim_(h->0) ((x+h)^2-x^2)/h = lim_(h->0) (cancel(x^2) +2hx + h^2 -cancel(x^2))/h`

`lim_(h->0) ((x+h)^2-x^2)/h = lim_(h->0) (2cancelhx+h^cancel2)/cancelh`

`lim_(h->0) ((x+h)^2-x^2)/h = lim_(h->0) (2x+h)`

`lim_(h->0) ((x+h)^2-x^2)/h = 2x`