How do you find the derivative of #(2x^2 +x - 3)/x#?
1 Answer
Feb 14, 2017
Explanation:
#(2x^2+x-3)/x#
#=(2x^2)/x+x/x-3/x#
#=2x+1-3x^-1# differentiate using the
#color(blue)"power rule"#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(ax^n)=nax^(n-1))color(white)(2/2)|)))#
#rArrd/dx(2x+1-3x^-1)#
#=2+3x^-2#
#=2+3/x^2#