What is the oxidation Number of sulfur in #SO_2# and #SO_3#?

1 Answer
Feb 15, 2017

+4 and +6

Explanation:

Total oxidation number of atoms in a compound is zero.

The more electronegative element exhibits its typical oxidation number, so in this case oxygen is the more electronegative element, so it exhibits oxidation number -2.

Therefore in #SO_2# the oxidation number of sulphur is #0 - (2.-2) = - (-4) = 4#

And in #SO_3# using the same calculation it equates to 6.