Question #0b531
1 Answer
Here's what I got.
Explanation:
You can find the work done by the force by looking at the displacement it produces.
You know that when a force
To match your scenario with the diagram, when the force
The work done by the force
#color(blue)(ul(color(black)(W = F * d * cosalpha)))#
Here
#d# is the displacement produced by the force#alpha# is the angle between the direction of the force and the direction of the displacement
In this case, the force is acting on the horizontal, which means that you have
#alpha = 0^@ implies cos alpha = 1#
Therefore, the work done by the force will be
#W = "100 N" * "5.0 m" = color(darkgreen)(ul(color(black)("500 J")))#
Power on the other hand, is the rate at which the work is being done. The power generated by a force is equal to the work done by said force per unit of time.
In other words, power,
#color(blue)(ul(color(black)(P = W/t)))#
Here
#t# represents the amount of time for which work is being done
In your case, you have
#P = "500 J"/"25 s" = color(darkgreen)(ul(color(black)("20 W"))) -># here#"W"# represents joules per second, or watts