How do you find the derivative of # y= ln (1 - x^2)#?
1 Answer
Feb 16, 2017
Explanation:
differentiate using the
#color(blue)"chain rule"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx[ln(f(x))]=1/(f(x))xx f'(x))color(white)(2/2)|))#
#y=ln(1-x^2)#
#rArrdy/dx=1/(1-x^2)xxd/dx(1-x^2)#
#color(white)(xxxxx)=-(2x)/(1-x^2)#
