How do you simplify #{4 (3-7) + 12}^2 / (-4) -3^3# using PEMDAS?

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Answer 1 · 2017-02-17T00:01:22

The answer is -31.

Step 1: #(4(3-7)+12)^2/-4-3^3#
Step 2: #(4*(-4)+12)^2/-4-27#
Step 3: #(-16+12)^2/-4-27#
Step 4: #(-4)^2/-4-27#
Step 5: #-4-27=-31#

Answer 2 · 2017-02-17T00:02:46

See the entire simplification process below:

First, we need to process the inner Parenthesis (P) containing #(3 - 7) = -4#:

#{4 xx -4 + 12}^2/-4 - 3^3#

Next, we can process the Multiplication (M) within the brackets or Parenthesis (P): #4 xx -4 = -16#

#{-16 + 12}^2/-4 - 3^3#

Then we can process the Addition (A) within the brackets (P) #{-16 + 12 = -4}#

#{-4}^2/-4 - 3^3#

Next, we can process the Exponents (E): #{-4}^2 = 16# and #3^3 = 27#:

#16/-4 - 27#

The we can process the Division (D) - #16/-4 = -4#:

#-4 - 27#

Now, we can complete the simplification by processing the Subtraction (S):

#-4 -27 = -31#