Question

Summer and Jason's present ages add up to `107` years. If `11` years ago Jason's age was four times Summer's age, how old is Jason now?

Answer 1

Jason is `79` years old now.

Explanation:

Let the Summer's age, `11` years ago, be `x` years. As `11` years ago Jason's age was four times Summer's age, Jason's age `11` years ago would have been `4x` years.

Hence, their present ages are `x+11` and `4x+11` and as sum of their ages now is `107` years, we have

`x+11+4x+11=107`

or`5x=107-11-11=85`

i.e. `x=85/5=17`

Hence, `11` years ago, Summer and Jason were `17` and `17xx4=68` years respectively.

and Jason is `68+11=79` years old now.