How do you write the expression for the nth term of the sequence given #1+1/2, 1+3/4, 1+7/8, 1+15/16, 1+31/32,...#?

1 Answer
Feb 17, 2017

#n^(th)# term of the sequence under consideration is #1+(2^n-1)/2^n#

Explanation:

Observe that each term has two components , one just #1# and the other, whose denominators are in the sequence #2,4,8,16,....# and numerator is just one less than the denominator .

As the #n^(th)# term of the sequence #2,4,8,16,....# is #2^n#

#n^(th)# term of the sequence under consideration is #1+(2^n-1)/2^n#