What is the area enclosed by #r=-cos(theta-(7pi)/4) # between #theta in [4pi/3,(5pi)/3]#?
1 Answer
Feb 17, 2017
Explanation:
The graph is a circle of radius 1/2, through pole, with center on
Despite that the non-negative r = sqrt(x^2+y^2) is
the higher limit
graph{(sqrt2(x^2+y^2)+x+y)(y+sqrt3x)(y-sqrt3x)=0 [-2.5, 2.5, -1.25, 1.25]}
Area=
from