#int sqrt(9-5x^2) dx# ?
I know that x=asintheta. But idk how to factor out so that i wont have #sqrt5#
I know that x=asintheta. But idk how to factor out so that i wont have
1 Answer
Feb 19, 2017
The answer is
Explanation:
We perform this integral by substitution
Let
and
So,
So,