Question

How do you solve `\frac { 4} { x - 6} + \frac { 3} { 6- x }`?

Answer 1

`4/(x-6)+3/(6-x)=1/(x-6)`

Explanation:

As `6-x=-(x-6)`,

`4/(x-6)+3/(6-x)`

= `4/(x-6)+3/(-(x-6))`

= `4/(x-6)-3/(x-6)`

= `(4-3)/(x-6)`

= `1/(x-6)`