How do you find the sum or difference of #(6ab^2+2ab)+(3a^2b-4ab+ab^2)#?

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Answer 1 · 2017-02-20T15:51:40

See the entire solution process below:

First, remove all the terms from parenthesis. Be care to handle the signs of the individual terms correctly:

#6ab^2 + 2ab + 3ab^2 - 4ab + ab^2#

Next, group like terms:

#3a^2b + 6ab^2 + ab^2 + 2ab - 4ab#

Now, combine like terms:

#3a^2b + 6ab^2 + 1ab^2 + 2ab - 4ab#

#3a^2b + (6 + 1)ab^2 + (2 - 4)ab#

#3a^2b + 7ab^2 - 2ab#