How do you simplify and write #c^-3/d^-5# with positive exponents?

Question

1719 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-20T14:57:13

See the entire simplification process below:

We will use these two rules of exponents to eliminate the negative exponents:

#x^color(red)(a) = 1/x^color(red)(-a)# and #1/x^color(blue)(a) = x^color(blue)(-a)#

#c^color(red)(-3)/d^color(blue)(-5) = d^color(blue)(- -5)/c^color(red)(- -3) = d^color(blue)(5)/c^color(red)(3)#

Answer 2 · 2017-02-20T16:02:45

#d^5/c^3#

#c^-3/d^-5#

#:.=c^-3-:d^-5#

#:.=1/c^3-:1/d^-5#

#:.=1/c^3-:(1/1)/(d^5)#

#:.=1/c^3 xx (1/1 xx d^5/1)#

#:.=1/c^3 xx d^5/1#

#:.=d^5/c^3#