How do you find x and y intercepts of # -3x + y = 6#?

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Answer 1 · 2017-02-20T19:12:57

#x-"intercept" = (-2,0)#

#y-"intercept" = (0,6)#

All along the #x#-axis, the #y#-value is zero.

All along the #y#-axis, the #x#-value is zero.

TO find the #x#-intercept make #y=0#

#-3x +y =6#

#-3x +0 =6#

#x = -2" "rarr" the point is " (-2,0)#

TO find the #y#-intercept make #x=0#

#-3x +y = 6#

#0 +y =6#

#y=6" "rarr" the point is " (0,6)#