A container with a volume of #36 L# contains a gas with a temperature of #240^o K#. If the temperature of the gas changes to #160 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-02-21T06:46:31

The new volume is #=24L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=36L#

#T_1=240K#

#T_2=160K#

#V_2=T_2/T_1*V_1#

#=160/240*36#

#=24L#