The gas inside of a container exerts #18 Pa# of pressure and is at a temperature of #350 ^o K#. If the temperature of the gas changes to #190 ^oK# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2017-02-21T10:00:27

The new pressure is #=9.77Pa#

We apply Gay Lussac's Law

#P_1/T_1=P_2/T_2#

#P_1=18Pa#

#T_1=350K#

#T_2=190K#

#P_2=T_2/T_1*P_1#

#=190/350*18#

#=9.77Pa#