If #15 L# of a gas at room temperature exerts a pressure of #5 kPa# on its container, what pressure will the gas exert if the container's volume changes to #3 L#?

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Answer 1 · 2017-02-22T07:08:31

The pressure is #=25kPa#

We apply Boyle's Law

#P_1V_1=P_2V_2#

#P_1=5kPa#

#V_1=15L#

#V_1=3L#

#P_2=V_1/V_2*P_1#

#=15/3*5=25kPa#