A container with a volume of #12 L# contains a gas with a temperature of #150^o C#. If the temperature of the gas changes to #490 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-02-22T14:29:46

The new volume is #=13.9L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=12L#

#T_1=150+273=423K#

#T_2=490K#

#V_2=T_2/T_1*V_1#

#=490/423*12=13.9L#