Question

Aidan is `18` years older than Summer. If he is `46` now, when was he twice her age?

Answer 1

See below.

Explanation:

Let Summer's age be `n`. Then Aidan's age is `n+18`. We're trying to find where `n+18=2n`, which can easily be solved for `n=18`.

So when Summer was `18`, Aidan was twice her age, `36`. If he is `46`, then he was twice her age `10` years ago.