2/a-2/b / 1/a^2 - 2/b^2 this is a division problem dealing with fractions and variables ? Algebra Expressions, Equations, and Functions Variable Expressions 1 Answer Shwetank Mauria Feb 23, 2017 #(2/a-2/b)/(1/a^2-2/b^2)=(2ab(b-a))/(b^2-2a^2)# Explanation: #(2/a-2/b)/(1/a^2-2/b^2# = #((2b-2a)/(ab))/((b^2-2a^2)/(a^2b^2))# = #(2b-2a)/(ab)xx(a^2b^2)/(b^2-2a^2)# = #(2(b-a))/(ab)xx(abxxab)/(b^2-2a^2)# = #(2(b-a))/cancel(ab)xx(cancel(ab)xxab)/(b^2-2a^2)# = #(2ab(b-a))/(b^2-2a^2)# Answer link Related questions How do you write the variable expression for: a quotient of 2 and the sum of a number and 3 ? What are variables? What are variable expressions? How do you write variable expressions? How do you evaluate variable expressions? How do you simplify the expression #3x-x+4#? How do you write a quotient of a number and 6 as an expression? How do you evaluate the expression #2x+1# for #x=1#? How do you write a product of a number and 2 as an expression? How do you write 5 less than 2 times a number as a variable expression? See all questions in Variable Expressions Impact of this question 1004 views around the world You can reuse this answer Creative Commons License