Question

Mixture containing .538mol `He` gas, .315mol `Ne` gas .103 `Ar` gas, is confined in 7.00-L vessel at `25^o`Celsius. How do you calculate partial pressure of each gas in mixture? How would you calculate the total pressure of the mixture?

Answer 1

`"Dalton's law of partial pressures states that........."`

Explanation:

`"Dalton's law of partial pressures states that in a gaseous"`
`"partial pressure exerted by a component gas is the same as"`
`"the pressure it would exert if it alone occupied the container."`

`"The total pressure is the sum of the individual partial pressures."`

Here `P_"Total"=P_"He"+P_"Ne"+P_"Ar"`

`=(n_"He"RT)/V+(n_"Ne"RT)/V+(n_"Ar"RT)/V`

`=(RT)/V(n_"He"+n_"Ne"+n_"Ar")`

You have the molar quantities; you have the temperature, and volume; you have `R=0.0821*L*atm*K^-1*mol^-1`. Have at it.