Question

A container with a volume of `32 L` contains a gas with a temperature of `480^o K`. If the temperature of the gas changes to `160 ^o K` without any change in pressure, what must the container's new volume be?

Answer 1

The new volume is `=10.7L`

Explanation:

We apply Charles' Law

`V_1/T_1=V_2/T_2`

`V_1=32L`

`T_1=480K`

`T_2=160K`

`V_2=T_2/T_1*V_1`

`=160/480*32`

`=10.7L`