A container with a volume of #19 L# contains a gas with a temperature of #160^o C#. If the temperature of the gas changes to #320 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-02-26T10:54:49

The new volume is #=14.04L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=19L#

#T_1=160+273=433K#

#T_2=320K#

#V_2=T_2/T_1*V_#

#=320/433*19#

#=14.04L#