How do you verify the identity #sin^2alpha-sin^4alpha=cos^2alpha-cos^4alpha#?

Question

8868 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-26T20:21:19

#"please look at the fallowing solution."#

#sin^2 alpha-sin^4 alpha=color(red)(cos^2 alpha-cos^4 alpha)#

#"let " sin^2 alpha -sin^4 alpha =k#

#sin^2 alpha=1-cos^2 alpha#

#sin^4 alpha=(1-cos^2 alpha)^2=1-2 cos^2 alpha+ cos^4 alpha#

#k=1-cos^2 alpha-(1-2cos^2 alpha +cos^4 alpha)#

#k=cancel(1)-cancel(cos^2) alpha cancel(-1)+cancel(2cos^2) alpha -cos^4 alpha#

#k=color(red)(cos^2 alpha-cos^4 alpha)#