First, we will use these rules for exponents to simplify the term on the left: color(red)((4/7m)^2)(47m)2: a = a^color(red)(1)a=a1 and (x^color(red)(a))^color(blue)(b) = x^(color(red)(a) xx color(blue)(b))(xa)b=xa×b
color(red)((4/7m)^2)(49m)(17p)(1/34p^5) =(47m)2(49m)(17p)(134p5)=
color(red)((4^1/7^1m^1)^color(blue)(2))(49m)(17p)(1/34p^5) =(4171m1)2(49m)(17p)(134p5)=
color(red)((4^(1xxcolor(blue)(2))/7^(1xxcolor(blue)(2))m^(1xxcolor(blue)(2)))(49m)(17p)(1/34p^5) = (41×271×2m1×2)(49m)(17p)(134p5)=
(4^2/7^2m^2)(49m)(17p)(1/34p^5) = (4272m2)(49m)(17p)(134p5)=
(16/49m^2)(49m)(17p)(1/34p^5)(1649m2)(49m)(17p)(134p5)
Next, we can rewrite this expression as:
(16/49m^2 xx 49m)(17p xx 1/34p^5)(1649m2×49m)(17p×134p5)
Then, factor and cancel the coefficients:
(16/color(red)(cancel(color(black)(49)))m^2 xx color(red)(cancel(color(black)(49)))m)(color(blue)(cancel(color(black)(17)))p xx 1/(color(blue)(cancel(color(black)(17)))2)p^5) =
(16m^2 xx m)(p xx 1/2p^5)
We can then use this rule of exponents to simplify the variables:
x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))
(16m^color(red)(2) xx m^color(blue)(1))(p^color(red)(1) xx 1/2p^color(blue)(5)) =
(16m^(color(red)(2)+color(blue)(1)))(1/2p^(color(red)(1)+color(blue)(5))) =
(16m^3)(1/2p^6)=#
(16m^3p^6)/2 =
8m^3p^6