How do you write #44^(1/6)# in radical form?

1 Answer
seol
Feb 28, 2017

#\root[6]{44}#

Explanation:

Template standard: given format...

#a^(b/c)#

converting to radical format generates the form

#\root[c]{a^b}#

Please note that this is not a square root! It is a root function that varies depending on the value of #c#.

You are given the problem #44^(1/6)#. Based on the template, the respective variables are as follows:
#a=44#, #b=1#, #c=6#
Now applying this to the radical format:

#\root[c]{a^b}\leftrightarrow\root[6]{44^1}#

Since anything to the #1^{th}# power is the number itself, your answer is...

#\root[6]{44}#

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