Question

How do you sketch the angle whose terminal side in standard position passes through (-8,-6) and how do you find sin and cos?

Answer 1

`sin t = - 3/5`
`cos t = - 4/5`

Explanation:

Call t the angle whose terminal side passes through point M (-8, -6):
t is located in Quadrant 3.
The hypotenuse `OM = sqrt(6^2 + 8^2) = sqrt100 = 10`
`sin t = - 6/10 = - 3/5`
`cos t = - 8/10 = - 4/5`