How do you long divide $(x^{4} + 10 x^{3} + 8 x^{2} - 59 x + 40) \div (x^{2} + 3 x - 5)$ $(x^4+10x^3+8x^2-59x+40) div (x^2+3x-5)$ ?

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How do you long divide $(x^{4} + 10 x^{3} + 8 x^{2} - 59 x + 40) \div (x^{2} + 3 x - 5)$ $(x^4+10x^3+8x^2-59x+40) div (x^2+3x-5)$ ?

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Answer 1 · 2017-02-28T10:15:52

The remainder is $= 0$ $=0$ and the quotient is $= (x^{2} + 7 x - 8)$ $=(x^2+7x-8)$

Explanation:

Let's perform the long division

$a a a a$ $color(white)(aaaa)$ $x^{4} + 10 x^{3} + 8 x^{2} - 59 x + 40$ $x^4+10x^3+8x^2-59x+40$ $a a a a$ $color(white)(aaaa)$ $∣$ $|$ $x^{2} + 3 x - 5$ $x^2+3x-5$

$a a a a$ $color(white)(aaaa)$ $x^{4} + 3 x^{3} - 5 x^{2}$ $x^4+3x^3-5x^2$ $a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaa)$ $∣$ $|$ $x^{2} + 7 x - 8$ $x^2+7x-8$

$a a a a a$ $color(white)(aaaaa)$ $0 + 7 x^{3} + 13 x^{2} - 59 x$ $0+7x^3+13x^2-59x$

$a a a a a a a$ $color(white)(aaaaaaa)$ $+ 7 x^{3} + 21 x^{2} - 35 x$ $+7x^3+21x^2-35x$

$a a a a a a a a a$ $color(white)(aaaaaaaaa)$ $+ 0 - 8 x^{2} - 24 x + 40$ $+0-8x^2-24x+40$

$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $- 8 x^{2} - 24 x + 40$ $-8x^2-24x+40$

$a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaa)$ $- 0 - 0 + 0$ $-0-0+0$

The remainder is $= 0$ $=0$ and the quotient is $= (x^{2} + 7 x - 8)$ $=(x^2+7x-8)$

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How do you long divide $(x^{4} + 10 x^{3} + 8 x^{2} - 59 x + 40) \div (x^{2} + 3 x - 5)$ $(x^4+10x^3+8x^2-59x+40) div (x^2+3x-5)$ ?

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Explanation:

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Math

Humanities

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How do you long divide (x4+10x3+8x2−59x+40)÷(x2+3x−5) (x^4+10x^3+8x^2-59x+40) div (x^2+3x-5)?

1 Answer

Explanation:

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Impact of this question

How do you long divide $(x^{4} + 10 x^{3} + 8 x^{2} - 59 x + 40) \div (x^{2} + 3 x - 5)$ $(x^4+10x^3+8x^2-59x+40) div (x^2+3x-5)$ ?