How do you solve #-7/9s = -1/3#?

1 Answer
Feb 28, 2017

See the entire solution process below:

Explanation:

Multiply each side of the equation by #-color(red)(9)/color(blue)(7)# to solve for #s# while keeping the equation balanced:

#-color(red)(9)/color(blue)(7) xx -7/9s = -color(red)(9)/color(blue)(7) xx -1/3#

#cancel(-color(red)(9))/cancel(color(blue)(7)) xx color(blue)(cancel(color(black)(-7)))/color(red)(cancel(color(black)(9)))s = -color(red)(3 xx 3)/color(blue)(7) xx -1/3#

#s = -color(red)(cancel(3) xx 3)/color(blue)(7) xx -1/color(red)(cancel(color(black)(3)))#

#s = -3/7 xx -1#

#s = 3/7#