A container with a volume of #7 L# contains a gas with a temperature of #290^o C#. If the temperature of the gas changes to #580 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-02-28T20:23:56

The new volume is #=7.21L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=7L#

#T_1=290+273=563K#

#T_2=580K#

#V_2=T_2/T_1*V_1#

#=580/563*7#

#=7.21L#