What is the derivative of #-2/(2x-4)^2#?
1 Answer
Mar 1, 2017
# d/dx -2/(2x-4)^2 =1/(x-2)^3 #
Explanation:
# d/dx -2/(2x-4)^2 = d/dx -2/((2(x-2))^2) #
# " "= d/dx -2/(4(x-2)^2) #
# " "= d/dx -1/2 (x-2)^(-2) #
So applying the power rule we get;
# d/dx -2/(2x-4)^2 = -1/2 (-2)(x-2)^(-3) #
# " "= 1(x-2)^(-3) #
# " "= 1/(x-2)^3 #
